Distance Between Points

[Marvin_Martian]

CloudCompare_9JnZjuE4QK.png (6.66 KiB) Viewed 1646 times

I'm trying to understand the distance between these two points. I understand the distance is 0.4 between points but the other values I do not understand ?

[daniel]

Well, that's simply the shift between the points along the X, Y or Z dimension (left column) or in the XY, XZ and ZY planes (right column = 2D distances)

[Marvin_Martian]

Well, that's simply the shift between the points along the X, Y or Z dimension (left column) or in the XY, XZ and ZY planes (right column = 2D distances)

If I understand correctly based on the screen capture, deltaX is the shift between the points, meanwhile deltaXY is the distance between the points in the XY axis ?

Meanwhile, the distance is simply the distance in mm between points ?

[daniel]

Yes,

In more mathematical terms, if the 2 points are named P and Q :
dX = P.x - Q.x
dXY = sqrt((P.x - Q.x)^2 + (P.y - Q.y)^2)
distance = sqrt((P.x - Q.x)^2 + (P.y - Q.y)^2 + (P.z - Q.z)^2)

[Marvin_Martian]

Yes,

In more mathematical terms, if the 2 points are named P and Q :
dX = P.x - Q.x
dXY = sqrt((P.x - Q.x)^2 + (P.y - Q.y)^2)
distance = sqrt((P.x - Q.x)^2 + (P.y - Q.y)^2 + (P.z - Q.z)^2)

In the math sense if R.x = 0.400002 and Q.x = 0.400007 = -0.000005 based on dX = R.x - Q.x ?

[daniel]

Not sure to fully understand the question, but yes, dX = R.x - Q.x = -0.000005

[Marvin_Martian]

Not sure to fully understand the question, but yes, dX = R.x - Q.x = -0.000005

Based on the math equation above if those two points existed at 0.400002 and 0.400007 then the offset would be -0.000005. :)